PROPOSALS TO THE CHESS WORLD
in regards to DOUBLE ELIMINATION KNOCK OUT TOURNAMENTS,
THE FUTURE PLAYERS CHESS CHAMPIONSHIP...
By: The Chess Champ
(I have many more great ideas and if you want to use
this anywhere, make sure you say it's from the CHESS CHAMP)
IT MAY TAKE YOU HOURS TO UNDERSTAND BUT TRUST ME,
THIS IS A CORRECT WAY OF DOING IT...
The best solution is:
Two games per day, 4 games total in A group
(plus elimination games on the second day).
The B group will have to play 2 games per day and finish it all the same day.
The B group would have to accept the fact they dont get
as much money as the A group. Also there will be no
retractions of extra dough $ in case if a round goes to the play-offs or not.
This way we will be sure we find the best player -
USING THE CHESS CHAMP'S DOUBLE ELIMINATION FORMULA/SYSTEM:
Some time ago... I spent many hours and many days on hot summer nights
until 5 am trying to find a lasting solution...
(mathematics involvement was of essence)
The double knock out tournament has been suggested a
long time ago but as usual they were unable to find
the right formula... they did not calculate it far enough
and did not cover many loop-holes...
Well, here's the thing:
First of all, we need to have more games.
The A group has the best of 4 games for each player in
first rounds. Two games for each day.
120/game + 15 sec per move, I believe that would
amount to no more than 5 hours per game + 1 hour break
+ enough time to finish the last game.
If a match is tied they play 2 x 30/g, if that is tied,
2 x 15/g and if still tied... then we go into 7/game
SUDDEN DEATH BUT NO DRAW ODDS.
Play must go on until somebody wins or gives up.
(or gets sick or something)
We start with 128 players; now the next round has 64
playas (and shakas):)
The first 64 players move into the Victor's bracket,
the Losers into Looser's column.
The number of players must remain even in every round, even
in a sense of divisibility by 2... 128, 64, 32, 16, 8, 4, 2, 1.
So when 64 players in the Losers column loose again,
they are gone, now we have 32 players + 32 players
from the Victor's camp, 64 again. (Losers)
Note, here's where the problem starts, the Victor's
column has 32 players and the Losers have 64 players.
The players in that column would have to play either
faster time controls or have a different time schedule
apart from the victor's column, they would also have
to accept the fact they get much less money than the
people in the A group. (as mentioned above)
But... at least they are alive...
Let's call the Losers B group... The B group
will have to play 2 times against a different opponent
to catch up with the A group. (All counted as one round)
Now, the A group eliminates again and they have 16
players, the B group also has 16 players remaining...
The A group eliminated 8 & those 8 join the 16, now we
have 24 players in B group... SOMETHING'S FISHY.
Problem !!! WARNING, ALERT, ACHTUNG...
This is an example how things can easily go wrong.
OK, SO THAT'S INCORRECT, IT CAN NOT BE LIKE THAT.
Well, when the 64 players in the B group loose, they
have 32 players left, while the A group of 64 is also down to 32.
So when that round is finished the B group accepts the 16 Losers
from the A group (now they have 16 players left and
the B group has 48) the 48 players engage in the battle. Again just
like the A group, for one round because...
48:2:2:2:2 = 24, 12, 6, 3 players, again not good.
So the round in group B has 24 players remaining.
The A group has 8 players.
Now things change...
The A group sends those 8 Losers to the B group and that's 32 players
again... Now we are cooking, in business again.
Again... problem... These 32 players in B group can
not play one round and have 16 players left, it's not
so simple... (just like life) They'd be left with 16 players and
would have to accept 4 players from round A.
That would amount 20 players and again there's no parity.
So, we have a problem again... AAAAAAAAAAGHHHHHHHH!!!
Well... not really, it's easy, it's elementary my dear Watson...
The A group is left with 8 players. Note.. this time we have
more games in group A in order to be
eliminated but the B group can not have same amount of
games until the semi finals because:
1. It would take way too long; 2. Sponsors get upset or whatever they do...)
So this time, the B group must play between each other
three times before they accept additional Losers from the A group.
Each round within this round (I call it inround) is still 2 games per inround.
So the number of players shrinks to 32, 16, 8, 4.
Now we have 4 players left in each group going into the next round.
However, the B group needs to accept the 4 Losers.
(This is the semi finals for group & the quarter & semi finals for the B group)
-All the rounds must be parallel, coincide, be congruent, superpose, superimpose
with each other and be in line with group A and all that sort of jazz.
In the meantime the A group will also have 4 players left but
those 4 players will play 4 games of normal time
control for four consecutive days...
(no more two games per day) In order to find the best challenger and to
give time to the other group to cath up,
the time control is 120/40 60/20 sd/30 + 15 seconds increment.
The B group can not afford that and they will play 2 games per day.
They will also have 4 games total with 120/G + 15 seconds increment.
There will be one day break for the A group.
he meantime the A group will also have 4 players left but
those 4 players will play 4 games of normal time
control for four consecutive days...
(no more two games per day) In order to find the best challenger and to
give time to the other group to cath up,
the time control is 120/40 60/20 sd/30 + 15 seconds increment.
The B group can not afford that and they will play 2 games per day.
They will also have 4 games total with 120/G + 15 seconds increment.
There will be one day break for the A group.
er location. Change of menu.
Or we can have all 8 players joined into one group and have them eliminate
each other from that point on.
In order to continue with two groups, it's getting very complicated...
The B group must now accept the 2 Losers from group A, so that is 6
players, again that number brings forth an odd number
of players. No clear parity.
So, in order to continue with the double knockout elimination...
The B group just finished their 8 group round of 4 games and
has 4 players left, the B group had 32, 16, 8, 4 players and
now they have two players left.
(Two games per day, one day elimination format)
The A group starts the next round of 4 semi-finalists. Four games, four days.
This round produces two Winners and two Losers.
(In the meantime the B group will relax awaiting the 2 Losers)
The two Losers join the B group of four players in B group semi-finals.
In the meantime the A group will relax until the B group gets down
to two players. All these games may take many days but it's worth it.
The B group switches to normal time control and plays four games, four days.
(This is semi-finals of group A and semi-finals of the group B)
Next, the group A will play six games in their finals.
While the A group of 2 starts their finals of 6 games leaving one player
standing, the B group plays a 6 game match with one player standing.
Next... the Looser from the finals in Group A match must
play 6 games match with the finalist of Group B.
Only then we will have the real finalist of the Group B.
In the meantime, the Winners of Group A is relaxing.
Finally, where there is a Winners in Group B and Group A there will be
a 12 game (or more) finals match.
The Winners will be known as The WORLD PLAYER CHAMPION.
Again, it may be very hard to hold 4 games for each
of these rounds but it's important in getting a true, enduring, best player.
The problem starts with the elimination of 32 players
in Group B... While there are 8 players left in A group, quarterfinalists,
the group B of 32 players can also be called
the quarterfinalist.
The whole point of this tournament is to find the
best challenger for the true champion. The champion
will await the challenger some time in the future.
(Usually, no longer than 6 months after this is over)
The Champion should be given the draw odds...
(no draw allowed before 30 moves, except if there's a repetition
or position requires it, out of 16 games, 6 openings should be
chosen from my 468 Lottery) That is, if after 16 games the match is tied,
they play additional 6 games with 120 mins + 15 sec increments time control
and if that is tied, the champion remains champion. One game for each day.
The World Championship must be played every two years,
let's say during the even years, during the odd years we can organize
the players championship, interzonals, zonals, etc...
I dont consider this knockout system thing to be a
real world championship (especially with 6 games final, way too short)
but a great way to find the challenger.
This is the mumbo-jumbo we get,
but at least it's fair to call this DOUBLE ELIMINATION
TOURNAMENT A TRUE D.E. TOURNAMENT FROM THE START TO THE END.
I spent lots of time on this. There were many problems in calculations
including days for relaxation of the players who are awaiting their opponent
in the later stages of the tournament, to the number of games needed to
be played in each round to making some sense out of it all,
for the good and fairness to all !!!
Here's the model:
GROUP A + B = 128 PLAYERS (Round 1)
PLAYERS REMAINING:
GROUP A GROUP B (Losers)
Round 2: 64 64
Round 3: 32 (32+32)=64; Rnd 3b: 32+16= 48
Round 4: 16 24
Round 5: 8 32; Rnd 5b = 16; Rnd 5c = 8; Rnd 5d = 4; Rnd 5e = 2;
Round 6: 4 4: (Rnd 5e + Rnd 6 Losers)
Round 7: 2 2
Round 8: 1 2; Rnd 8b 2 ( Rnd 8 + Round 1 Winner )
Round 9: FINALS
Or we can just have 4 games knockout per round, no Double Elimination.
But we will have more games.
For similar info:
geocities.com/chesschampby2k/Unify.txt